A python program to count the number of digits in a number.
Under this post i am going to provide you the explanation of a python program to count the number of digits in a number.
For example if a number is 12345 then your program should print 5, since the number contains 5 digits.
Here the ‘count’ is initialized to zero. Take input from the user and create a variable for storing the input by the user. By using a while loop every time the ‘num’ changes to num//10.Let 12 be the ‘num’ here and then 12//10 is 1.Increment the ‘count’ by 1.Repeat the same process until the ‘num’ becomes zero.Finally print the output.
Output
Give any number: 524 #Case 1 Total digits are: 3 Give any number: 002 #Case 2 Total digits are: 1
Give any number: 1.24 #Case 3 Total digits are: 1
Give any number: 123.456 #Case 4 Total digits are: 3 |
If you observe the output of case 3 and case 4 as well, the digit before the decimal point is printed and rest of the part is ignored.
We can also count the number of digits in a number by the following way:
Output
Any number: 12364767
Total digits : 8 |
‘abs’ is used to get the absolute value of a number. i.e. to handle the case even if there occurs negative value.